What? This appears similar to the forces for the balloon? OK, it does glance an identical—however there may be a large distinction. For the balloon, there may be that upward-pushing buoyancy drive, and it is only one worth. It does not trade when the wind velocity will increase. For the kite, the upward pushing drive is the elevate, and it DOES rely on the wind velocity. So it isn’t the identical. Just believe the case when there may be 0 wind. The drag drive will likely be 0, which means that the elevate is 0. The kite may not fly—it simply falls down and it is unhappy.
Again, I am getting two drive equations that I will use to do away with the unknown worth of T. With that, I am getting the following expression for the attitude of the kite (θokay). Actually, I put a subscript okay on a bunch of stuff so it’s essential to see it is other than the values for the balloon. Oh, air nonetheless has the identical density for each gadgets.
OK, I’m about to make a plot of the flying attitude for each the balloon and a kite at other wind speeds. But earlier than I do this, let’s take into accounts the minimal velocity to fly this kite. In order to elevate off the flooring, the elevate drive will have to be no less than equivalent to the weight of the kite. I will then resolve this for the wind velocity. Anything not up to this and you will not have a flying kite.